Sidious Posted August 25, 2001 Share Posted August 25, 2001 Just found this over at the ww forums figured it deserved a reprint here."Montano - 08/25/2001 14:19:29 - bruce-baugh@spiretech.com Mad props here to veteran gamer Carl Rigney for doing the math for me. Feel free to save and repost this, preferably leaving in the acknowledgement.THE FORMULA: N successes at difficulty X become T successes at target 7:T = 4N / (10 - X)THE CHART:The rows are WoD target numbers.The columns are numbers of successes needed. Find the match of target and successes to get the number of Aeon Continuum successes needed.+-- difficulty||V1 2 3 4 5 <-- number of successes2 1 1 2 2 33 1 1 2 2 34 1 1 2 3 35 1 2 2 3 46 1 2 3 4 57 1 3 4 5 78 2 4 6 8 109 4 8"It's great that Bruce did this. Link to comment Share on other sites More sharing options...
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